2x^2-5x=3x^2-12x+31

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Solution for 2x^2-5x=3x^2-12x+31 equation: 



2x^2-5x=3x^2-12x+31

We move all terms to the left:

2x^2-5x-(3x^2-12x+31)=0

We get rid of parentheses

2x^2-3x^2-5x+12x-31=0

We add all the numbers together, and all the variables

-1x^2+7x-31=0

a = -1; b = 7; c = -31;
Δ = b2-4ac
Δ = 72-4·(-1)·(-31)
Δ = -75
Delta is less than zero, so there is no solution for the equation

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